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Salesforce Sharing-and-Visibility-Architect exam
  • Exam Code: Sharing-and-Visibility-Architect
  • Exam Name: Salesforce Certified Sharing and Visibility Architect
  • Version: V12.35
  • Q & A: 70 Questions and Answers
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NEW QUESTION: 1

Select and Place:

Answer:
Explanation:

Explanation:
-Service Manager
http://technet.microsoft.com/en-us/library/hh519626.aspx
-App Controller
http://technet.microsoft.com/en-us/library/hh546834.aspx
-Operation Manager
http://technet.microsoft.com/en-us/library/hh212908.aspx

NEW QUESTION: 2
JIT strives for an economic order quantity of what?
A. Less than 1 but greater than 0
B. 0
C. 1
D. Greater than 1
Answer: B
Explanation:
JIT strives for an economic order quantity of one. This is really a goal as it may not be
practical, but it is the goal of a JIT program.

NEW QUESTION: 3
You have a server named Server1 that runs Windows Server 2012 R2.
You plan to enable Hyper-V Network Virtualization on Server1.
You need to install the Windows Network Visualization Filter Driver on Server1.
Which Windows PowerShell cmdlet should you run?
A. Set-NetVirtualizationGlobal
B. Add - WindowsFeature
C. Enable-NetAdapterBinding
D. Set-NetAdapterVmq
Answer: C
Explanation:
Hyper-V Network Virtrtualization runs multiple virtual networks on a physical network. And each virtual network operates as if it is running as a physical network. The Set- NetAdaptercmdlet sets the basic properties of a network adapter such as virtual LAN (VLAN) identifier (ID) and MAC address. Thus if you add the binding parameter to the command then you will be able to install the Windows Network Virtualization Filter Driver.
Step one:
Enable Windows Network Virtualization (WNV). This is a binding that is applied to the NIC that you External Virtual Switch is bound to. This can be a physical NIC, it can be an LBFO NIC team. Either way, it is the network adapter that your External Virtual Switch uses to exit the server.
This also means that if you have multiple virtual networks or multiple interfaces that you can pick and choose and it is not some global setting.
If you have one External Virtual Switch this is fairly easy:
$ vSwitch = Get-VMSwitch -SwitchType External
# Check if Network Virtualization is bound
# This could be done by checking for the binding and seeing if it is enabled ForEach-Object -InputObject $vSwitch { if ((Get-NetAdapterBinding -ComponentID "ms_netwnv" -InterfaceDescription
$ _.NetAdapterInterfaceDescription).Enabled -eq $false){
# Lets enable it
Enable-NetAdapterBinding -InterfaceDescription $_.NetAdapterInterfaceDescription - ComponentID "ms_netwnv"
}
}

NEW QUESTION: 4
Which of the following is NOT an issue with secret key cryptography?
A. Compromise of the keys can enable the attacker to impersonate the
key owners and, therefore, read and send false messages.
B. Secure distribution of the keys.
C. A networked group of m users with separate keys for each pair of
users will require m (m-1)/2 keys.
D. Security of the certification authority.
Answer: D
Explanation:
The CAis used in public key cryptography, not secret key cryptography.
A CA will certify that a public key actually belongs to a specific
individual and that the information associated with the
individual's key is valid and correct. The CA accomplishes this certification by digitally signing the individual's public key and associated information. The certification professes to another person who
wants to send a message to this individual using public key encryption
that the public key actually belongs to the intended individual.
The Consultation Committee, International Telephone and Telegraph,
International Telecommunications Union (CCITT-ITU)/
International Organization for Standardization (ISO) X.509 Authentication framework defines a format for public key certificates. This structure is outlined in Figure.

image012
Answer "A networked group of m users with separate keys for each pair of users will require m (m-1)/2 keys" is an important issue in secret key cryptography; therefore it is not the correct answer. If, among a network of m users, each user wants to have secure communications with every other user on the network, then there must be a secret key for each pair of potential users.
This concept can be illustrated with five users as shown in Figure.

image014
Thus, with five users, the number of independent keys is equal to (5 x
4)/2 or 10 as depicted by the ten connecting lines in Figure A.6.
*answer "Secure distribution of the keys" is incorrect since securely distributing the keys to all users is, obviously, a very important requirement.
Answer d is incorrect since a compromise of the keys can, indeed,
enable the attacker to impersonate the key owners and, therefore,
read and send false messages.

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