030-444 Answers Real Questions, ACSM 030-444 Related Exams | Best 030-444 Practice - Hospital

ACSM 030-444 exam
  • Exam Code: 030-444
  • Exam Name: ACSM Certified Clinical Exercise Physiologist
  • Version: V12.35
  • Q & A: 70 Questions and Answers
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NEW QUESTION: 1
Which of the following types of encryption will help in protecting files on a PED?
A. Database encryption
B. Encrypted hidden container
C. Mobile device encryption
D. Transport layer encryption
Answer: C
Explanation:
Section: Application, Data and Host Security
Explanation/Reference:
Explanation:
Device encryption encrypts the data on a Personal Electronic Device (PED). This feature ensures that the
data on the device cannot be accessed in a useable form should the device be stolen.

NEW QUESTION: 2
Your company has a hybrid cloud between Azure and Azure Stack.
The company uses Azure DevOps for its CI/CD pipelines. Some applications are built by using Erlang and Hack.
You need to ensure that Erlang and Hack are supported as part of the build strategy across the hybrid cloud. The solution must minimize management overhead.
What should you use to execute the build pipeline?
A. AzureDevOps self-hosted agents on Hyper-V virtual machines
B. a Microsoft-hosted agent
C. AzureDevOps self-hosted agents on virtual machine that run on Azure Stack
D. AzureDevOps self-hosted agents on Azure DevTest Labs virtual machines.
Answer: C
Explanation:
Azure Stack offers virtual machines (VMs) as one type of an on-demand, scalable computing resource. You can choose a VM when you need more control over the computing environment.
References:
https://docs.microsoft.com/en-us/azure/azure-stack/user/azure-stack-compute-overview

NEW QUESTION: 3
The EMPLOYEES table contains these columns:
EMPLOYEE_ID NUMBER(4)
ENAME VARCHAR2 (25)
JOB_ID VARCHAR2(10)
Which SQL statement will return the ENAME, length of the ENAME, and the numeric position of the letter "a" in the ENAME column, for those employees whose ENAME ends with a the letter "n"?
A. SELECT ENAME, LENGTH(ENAME), SUBSTR(ENAME, -1,1) FROM EMPLOYEES WHERE INSTR(ENAME, -1, 1) = 'n';
B. SELECT ENAME, LENGTH(ENAME), SUBSTR(ENAME, -1,1) FROM EMPLOYEES WHERE INSTR(ENAME, 1, 1) = 'n';
C. SELECT ENAME, LENGTH(ENAME), INSTR(ENAME, ,-1,1) FROM EMPLOYEES WHERE SUBSTR(ENAME, -1, 1) = 'n';
D. SELECT ENAME, LENGTH(ENAME), INSTR(ENAME, 'a') FROM EMPLOYEES WHERE SUBSTR(ENAME, -1, 1) = 'n';
Answer: D
Explanation:
INSTR is a character function return the numeric position of a named string. INSTR(NAMED,'a') Incorrect
answer: BDid
not return a numeric position for 'a'. CDid not return a numeric position for 'a'. DDid not return a numeric position for 'a'.
Refer:Introduction toOracle9i:SQL, Oracle University Study Guide, 3-8

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