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NEW QUESTION: 1
If the solution designer wishes to ensure that subscribing MQ applications receive message from a topic even
if the subscribing MQ application is disconnected from the queue manager at the time the message is
published, which action is required?
A. The publishing application must set the subscription as durable.
B. The publishing application must set the message as persistent.
C. The subscribing application must set the message as persistent.
D. The subscribing application must set the subscription as durable.
Answer: D
NEW QUESTION: 2
View the exhibit and examine the structures of the EMPLOYEESand DEPARTMENTStables.
EMPLOYEES
Name Null? Type
- ---------------- ----- -------------
EMPLOYEE_ID NOT NULL NUMBER(6)
FIRST_NAME VARCHAR2(20)
LAST_NAME NOT NULL VARCHAR2(25)
HIRE_DATE NOT NULL DATE
JOB_ID NOT NULL VARCHAR2(10)
SALARY NUMBER(10,2)
COMMISSION NUMBER(6,2)
MANAGER_ID NUMBER(6)
DEPARTMENT_ID NUMBER(4)
DEPARTMENTS
Name Null? Type
----------------- ----- -------------
DEPARTMENT_ID NOT NULL NUMBER(4)
DEPARTMENT_NAME NOT NULL VARCHAR2(30)
MANAGER_ID NUMBER(6)
LOCATION_ID NUMBER(4)
You want to update EMPLOYEEStable as follows:
Update only those employees who work in Boston or Seattle (locations 2900 and 2700).

Set department_idfor these employees to the department_idcorresponding to London

(location_id 2100).
Set the employees' salary in location_id2100 to 1.1 times the average salary of their department.

Set the employees' commission in location_id2100 to 1.5 times the average commission of their

department.
You issue the following command:
SQL> UPDATE employees
SET department_id
( SELECT department_id
FROM departments
WHERE location_id = 2100),
( salary, commission)
( SELECT 1.1*AVG(salary), 1.5*AVG(commission)
FROM employees, departments
WHERE departments.location_id IN(2900, 2700, 2100))
WHERE department_id IN
( SELECT department_id
FROM departments
WHERE location_id = 2900
OR location_id = 2700;
What is outcome?
A. It generates an error because multiple columns (SALARY, COMMISSION)cannot be specified together in an UPDATEstatement.
B. It executes successfully but does not give the correct result.
C. It executes successfully and gives the correct result.
D. It generates an error because a subquery cannot have a join condition in a UPDATEstatement.
Answer: B
NEW QUESTION: 3
사용자가 마법사를 사용하여 CIDR 20.0.0.0/16이 포함된 VPC를 만들었습니다. 사용자가 공용 서브넷 CIDR (20.0.0.0/24) 및 VPN 전용 서브넷 CIDR (20.0.1.0/24)을 VPN 게이트웨이 (vgw-123456)와 함께 만들어 사용자의 데이터 센터에 연결했습니다. 사용자의 데이터 센터에 CIDR이 있습니다.
172.28.0.0/12. 또한 사용자는 VPN 서브넷에서 인터넷 트래픽을 허용하도록 NAT 인스턴스 (i-123456)를 설정했습니다. 아래에서 언급 한 옵션 중이 시나리오에서 주요 경로 테이블에 유효한 항목이 아닌 것은 무엇입니까?
A. 대상 : 0.0.0.0/0 및 대상 : i-123456
B. 대상 : 172.28.0.0/12 및 대상 : vgw-123456
C. 대상 : 20.0.0.0/16 및 대상 : 로컬
D. 대상 : 20.0.1.0/24 및 대상 : i-123456
Answer: D
Explanation:
설명:
사용자는 VPC 내의 요구 사항에 따라 서브넷을 만들 수 있습니다. 사용자가 자신의 데이터 센터에서 VPC에 연결하려는 경우 하드웨어 VPN 액세스를 사용하여 자신의 데이터 센터에 연결하는 공용 및 VPN 전용 서브넷을 설정할 수 있습니다. 사용자가 마법사를 사용하여이 설정을 구성하면 가상 사설 게이트웨이가 만들어져 VPN 서브넷의 모든 트래픽을 라우팅합니다. 사용자가 모든 인터넷 요청을 라우팅하기 위해 NAT 인스턴스를 설정 한 경우 인터넷에 대한 모든 요청을 해당 인스턴스로 라우팅해야합니다. 조직의 DC에 대한 모든 요청은 VPN 게이트웨이로 라우팅됩니다. 다음은이 시나리오에서 주요 경로 테이블에 대한 유효한 항목입니다.
목적지 : 0.0.0.0/0 및 대상 : i-123456 (모든 인터넷 트래픽을 NAT 인스턴스로 라우팅) 대상 : 172.28.0.0/12 및 대상 : vgw-123456 (모든 조직의 데이터 센터 트래픽을 VPN 게이트웨이로 라우팅 ) 대상 : 20.0.0.0/16 및 대상 : 로컬 (VPC에서 로컬 라우팅 허용)
http://docs.aws.amazon.com/AmazonVPC/latest/UserGuide/VPC_Scenario3.html