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    About FCP - FortiWeb 7.4 Administrator Exam Questions

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    NEW QUESTION: 1
    Which of the following statements best defines the Application Protection (Shielding and Enveloping) feature?
    A. Applications, system registry and services are locked down against malicious activity
    B. Applications are not permitted to access data, registry and services outside of their application envelope
    C. Applications can only hook into processes that match a specific digital signature
    D. Applications are prevented from communicating with any undefined network services
    Answer: A

    NEW QUESTION: 2
    Amazon EC2で実行されているアプリケーションが、Amazon RDS SQL Serverデータベースへの接続を開きます。開発者は、データベースのユーザー名とパスワードをコードに保存したくありません。開発者は、資格情報を自動的にローテーションしたいと考えています。
    データベースの資格情報を保存してアクセスするための最も安全な方法は何ですか?
    A. データベースにアクセスする権限を持つIAMロールを作成しますEC2インスタンスにロールをアタッチします
    B. AWSシークレットマネージャーを使用して認証情報を保存する必要に応じてシークレットマネージャーから認証情報を取得する
    C. ユーザー名とパスワードの資格情報をソースコードに直接保存します。ソースコードはプライベートリポジトリに保存されているため、これ以上のアクションは必要ありません。
    D. Amazon S3バケットの暗号化されたテキストファイルに認証情報を保存しますインスタンスの起動時にAmazon S3から認証情報をダウンロードするようにEC2インスタンスのユーザーデータを設定します
    Answer: B

    NEW QUESTION: 3
    The network administrator is asked to configure 113 point-to-point links. Which IP addressing scheme defines the address range and subnet mask that meet the requirement and waste the fewest subnet and host addresses?
    A. 10.10.0.0/18 subnetted with mask 255.255.255.252
    B. 10.10.0.0/23 subnetted with mask 255.255.255.252
    C. 10.10.1.0/24 subnetted with mask 255.255.255.252
    D. 10.10.1.0/25 subnetted with mask 255.255.255.252
    E. 10.10.0.0/16 subnetted with mask 255.255.255.252
    Answer: B
    Explanation:
    Explanation
    We need 113 point-to-point links which equal to 113 sub-networks < 128 so we need to
    borrow 7 bits (because 2

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      7 = 128).
      The network used for point-to-point connection should be /30.
      So our initial network should be 30 - 7 = 23.
      So 10.10.0.0/23 is the correct answer.
      You can understand it more clearly when writing it in binary form:
      /23 = 1111 1111.1111 1110.0000 0000
      /30 = 1111 1111.1111 1111.1111 1100 (borrow 7 bits)
      Topic 4, IP Routing Technologies

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