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NEW QUESTION: 1
Which of these is the equation used to derive a 64 Kbps bit rate?
A. 2 x 4 kHz x 8-bit code words
B. 2 x 8 kHz x 4-bit code words
C. 2 x 4-bit code words x 8 kHz
D. 8 kHz x 8-bit code words
Answer: A
Explanation:
Explanation/Reference:
Explanation:
While the human ear can sense sounds from 20 to 20, 000 Hz, and speech encompasses sounds from about 200 to 9000 Hz, the telephone channel was designed to operate at about 300 to 3400 Hz. This economical range carries enough fidelity to allow callers to identify the party at the far end and sense their mood. Nyquist decided to extend the digitization to 4000 Hz, to capture higher-frequency sounds that the telephone channel may deliver. Therefore, the highest frequency for voice is 4000 Hz. According to Nyquist theory, we must double the highest frequency, so 2x4kHz = 8kHz.
Each sample will be encoded into a 8-bit code. Therefore 8kHz x 8-bit code = 64 Kbps (notice about the unit Kbps: 8kHz = 8000 samples per second so 8000 x 8-bit = 64000 bit per second = 64 Kilobit per second = 64 Kbps) Reference: http://encyclopedia2.thefreedictionary.com/Nyquist+theorem Note:
Nyquist theory:
"When sampling a signal (e.g., converting from an analog signal to digital), the sampling frequency must be greater than twice the bandwidth of the input signal in order to be able to reconstruct the original perfectly from the sampled version."

NEW QUESTION: 2
ある会社は、AWSアカウントでAmazon EC2インスタンスを使用して、いくつかの異なるワークロードを処理しています。会社はそれぞれのコストを理解するために分析を実行する必要があります。ワークロード。この要件を満たすための最も運用効率の高い方法は何ですか？
A. ワークロードアプリケーションを更新して、使用状況データをコスト割り当てデータベースに公開します。
B. 各ワークロードのEC2インスタンスを個別のAWSアカウントに移動します。
C. ワークロードごとに異なるEC2インスタンスファミリーを使用します。
D. 各EC2インスタンスにコスト割り当てタグを追加し、タグをアクティブ化します
Answer: A

NEW QUESTION: 3
Click on the exhibit.

Given the contents of the LSPs from routers R1 and R2, which of the following is TRUE?
A. Neither router R1 nor router R2 summarizes the prefixes from router R3.
B. Router R1 summarizes the prefixes from router R3 as 192.168.0.0/20 and router R2 does not summarize the prefixes.
C. Router R1 summarizes the prefixes from router R3 as 192.168.0.0/16 and router R2 does not summarize the prefixes.
D. Router R1 does not summarize the prefixes from routers R3 and R2 summarizes them as
192.168.0.0/16.
E. Router R1 does not summarize the prefixes from routers R3 and R2 summarizes them as
192.168.0.0/20.
F. Both routers R1 and R2 summarize the prefixes from R3 as 192.168.0.0/20.
Answer: F