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NEW QUESTION: 1
電子メールの発信元をスプーフィングするために使用される技術は、送信者のインターネットプロトコル（IP）アドレスを正常に隠すことができますか？
A. Webクロール
B. オニオンルーティング
C. 仮想プライベートネットワーク（VPN）
D. 返信先データの変更
Answer: B

NEW QUESTION: 2
Click the Exhibit button.
[edit protocols ospf]
user@R2# show
area 0.0.0.6 {
nssa {
default-lsa default-metric 10;
area-range 184. 23. 12. 0/24;
}
interface ge-1/1/4;
}
[edit protocols ospf]
user@R2# show ospf database
OSPF database, Area 0.0.0.0
Type ID Adv Rtr Seq Age Opt Cksum Len
Router *192.168.0.2 192.168.0.2 0x80000004 749 0x22 0x87c2 60
Router 192.168.0.3 192.168.0.3 0x80000004 399 0x22 0x94b5 60
Summary *10.0.0.0 192.168.0.2 0x80000003 19 0x22 0xe2e4 28
Summary *192.168.0.1 192.168.0.2 0x80000002 1100 0x22 0xbda7 28
OSPF database, Area 0.0.0.6
Type ID Adv Rtr Seq Age Opt Cksum Len Router 192.168.0.1 192.168.0.1 0x80000004 404 0x20 0x76db 60 Router *192.168.0.2 192.168.0.2 0x80000003 1802 0x20 0x319b 48 Summary *11.0.0.0 192.168.0.2 0x80000002 2504 0x20 0xf5d3 28 Summary *192.168.0.2 192.168.0.2 0x80000003 2153 0x20 0xc5a0 28 Summary *192.168.0.3 192.168.0.2 0x80000002 398 0x20 0xc79d 28 NSSA *0.0.0.0 192.168.0.2 0x80000001 11 0x20 0xcbf1 36 NSSA 184.23.12.0 192.168.0.1 0x80000002 447 0x28 0xb93f 36
OSPF AS SCOPE link state database Type ID Adv Rtr Seq Age Opt Cksum Len Extern *184.23.12.0 192.168.0.2 0x80000003 11 0x22 0x28d6 36
Referring to the exhibit, which two statements are correct? (Choose two.)
A. R2 is an ABR.
B. R2 is an ASBR.
C. R2 injects a Type 5 LSA for 184.23.12.0/24 into the backbone.
D. R2 injects a Type 3 LSA for 184.23.12.0/24 into the backbone.
Answer: A,C

NEW QUESTION: 3
You are creating an application for computers that run Windows XP or later. This application must run after the computer starts. The user must not be aware that the application is running.
The application performs tasks that require permissions that the logged-in user does not have.
Which type of application allows this behavior?
A. Windows Service application
B. DOS batch file
C. Windows Forms application
D. Terminate-and-stay-resident (TSR) program
Answer: A