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Fortinet FCP_FGT_AD-7.6 exam
  • Exam Code: FCP_FGT_AD-7.6
  • Exam Name: FCP - FortiGate 7.6 Administrator
  • Version: V12.35
  • Q & A: 70 Questions and Answers
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NEW QUESTION: 1
Ein Kunde baut einen High-End-Gaming-PC und sucht nach einem geeigneten Netzteil. Welche der folgenden Funktionen eines Netzteils sollten installiert werden? (Wählen Sie DREI).
A. Doppelte 12-V-Schienen
B. 350-450 Watt Leistung
C. 20-poliger Hauptanschluss
D. Mini-ITX-Formfaktor
E. 24-poliger Hauptanschluss
F. Hohe Anzahl an Anschlüssen
Answer: A,E,F

NEW QUESTION: 2
You have an Azure subscription named Sub1 that is associated to an Azure Active Directory (Azure AD) tenant named contoso.com.
You are assigned the Global administrator role for the tenant. You are responsible for managing Azure Security Center settings.
You need to create a custom sensitivity label.
What should you do first?
A. Elevate access for global administrators in Azure AD.
B. Upgrade the pricing tier of the Security Center to Standard.
C. Enable integration with Microsoft Cloud App Security.
D. Create a custom sensitive information type.
Answer: D
Explanation:
Explanation
First, you need to create a new sensitive information type because you can't directly modify the default rules.
References:
https://docs.microsoft.com/en-us/office365/securitycompliance/customize-a-built-in-sensitive-information-type

NEW QUESTION: 3
Which one of the following queries selects the customer whose order has the highest total price?
A. CriteriaBuilder cb = ...
Criteria Query <Customer> cq = cb.create Query (Customer.class);
Root<Customer> c = cq.from(Customer.class);
Join<Customer, Order> o = c.join(Customer__.orders);
cq.select(c).distinct(true);
Subquery<Double> sq = cq.subquery(Double.class);
Root<Order> subo = cq.correlate(o);
sq.select(cb.max(subo.get(Order_.totalPrice)));
cq.where(cb.equal(o.get(Order_.totalPrice), cb.all(sq)));
B. CriteriaBuilder cb = ...
CriteriaQuery<Customer> cq = cb.createquery(customer.class)
Root<Customer> c = cq.from(Customer.class);
Join<Customer, Order> o = c.join(Customer__.orders);
cq.select(c).distinct(true);
Subquery<Double> sq = cq.subquery(Double.class);
Root<Order> subo = cq.correlate(o);
sq.select(cb.max(subo.get(Order_.totalPrice)));
cq.where(cb.equal(o.get(Order_.totalPrice), cb.all(sq)));
C. CriteriaBuilder cb = ...
CriteriaQuery<Customer> cq = cb.cteateQuery(Customer.class);
Root<Customer> c = cq.from(Customer.class);
Join<Customer, Order> o = c.join(Customer__.orders);
cq.select(c).distinct(true);
Subquery<Double> sq = cq.subquery(Double.class);
Root<Order> subo = cq.correlate(o);
sq.select(cb.max(subo.get(Order_.totalPrice)));
cq.where(cb.equal(o.get(Order_.totalPrice), cb.all(sq)));
D. CriteriaBuilder cb = ...
CriteriaQuery<Customer> cq = cb.createQuery(Customer.class);
Root<Customer> c = cq.from(Customer.class);
Join<Customer, Order> o = c.join(Customer_.orders);
cq.select(c).distinct(true);
Subquery<Double> sq = cq.subquery(Double.class);
Root<Order> subo = sq.from(Order.class);
sq. select (ci: . max ( subo . get (Order_ . Total Price) ) ) ;
cq.where(sq.all(o.gei(Order_.totalPrice)));
Answer: B

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