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NEW QUESTION: 1

A. Option A
B. Option D
C. Option C
D. Option B
Answer: A
Explanation:
https://technet.microsoft.com/en-us/library/gg712322.aspx

NEW QUESTION: 2
A customer needs a cost-effective sales solution that can display current news about a lead or an account.
You recommend Microsoft Relationship Sales.
Which two products are includes in Microsoft Relationship Sales? Each correct answer presents part of the solution.
NOTE. Each correct selection is worth one point.
A. Dynamics 365 Sales Enterprise
B. Dynamics 365 Customer Insights
C. Dynamics 365 Sales Insights
D. Dynamics Sales navigator
Answer: A,D

NEW QUESTION: 3
Which standard access control entry permits from odd-numbered hosts in the 10.0.0.0/24 subnet?
A. Permit 10.0.0.0.0.0.0.1
B. Permit 10.0.0.1.0.0.0.254
C. Permit 10.0.0.1.0.0.0.0
D. Permit 10.0.0.0.255.255.255.254
Answer: B
Explanation:
Remember, for the wildcard mask, 1's are I DON'T CARE, and 0's are I CARE. So now let's analyze a simple ACL:
access-list 1 permit 172.23.16.0 0.0.15.255
Two first octets are all 0's meaning that we care about the network 172.23.x.x. The third octet of the wildcard mask, 15 (0000 1111 in binary), means that we care about first 4 bits but don't care about last 4 bits so we allow the third octet in the form of 0001xxxx (minimum:00010000 = 16; maximum: 0001111 = 31).

The fourth octet is 255 (all 1 bits) that means I don't care.
Therefore network 172.23.16.0 0.0.15.255 ranges from 172.23.16.0 to 172.23.31.255.
Now let's consider the wildcard mask of 0.0.0.254 (four octet: 254 = 1111 1110) which means we only care the last bit. Therefore if the last bit of the IP address is a "1" (0000 0001) then only odd numbers are allowed. If the last bit of the IP address is a "0" (0000 0000) then only even numbers are allowed.
Note: In binary, odd numbers are always end with a "1" while even numbers are always end with a "0".
Therefore in this question, only the statement "permit 10.0.0.1 0.0.0.254" will allow all oddnumbered hosts in the 10.0.0.0/24 subnet.