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NEW QUESTION: 1
The internal audit department is investigating a possible breach of security. One of the auditors is sent to interview the following employees:
Employee A Works in the accounts receivable office and is in charge of entering data into the finance system.
Employee B Works in the accounts payable office and is in charge of approving purchase orders.
Employee C Is the manager of the finance department, supervises Employee A and Employee B, and can perform the functions of both Employee A and Employee B.
Which of the following should the auditor suggest be done to avoid future security breaches?
A. Employee A and Employee B should rotate jobs at a set interval and cross-train.
B. The manager should only be able to review the data and approve purchase orders.
C. All employees should have the same access level to be able to check on each other's.
D. The manager should be able to both enter and approve information.
Answer: B

NEW QUESTION: 2
Exhibit:

You are a news reporter. You have a been given the assignment to give a history of the Olympic Games.
Task 1:
In cell B2 of the "No Medals" worksheet add a formula that uses a single function to look up the country code in the "IOC Teams" worksheet for the country listed in a cell A2 of the "No Medals" worksheet.
Answer:
Explanation:
See the explanation below.
Explanation
Use VLOOKUP and give the parameters as mentioned in the question

NEW QUESTION: 3
どのADMフェーズがアーキテクチャ開発イニシアチブの範囲を定義し、アーキテクチャ開発を進めるための承認を取得しますか？
A. フェーズA：アーキテクチャビジョン
B. 予備段階
C. 要件管理
D. フェーズB：ビジネスアーキテクチャ
E. フェーズD：テクノロジーアーキテクチャ
Answer: A
Explanation:
Reference https://pubs.opengroup.org/architecture/togaf9-doc/arch/chap06.html

NEW QUESTION: 4
Sie sind Datenbankentwickler für eine Anwendung, die auf einem Microsoft SQL Server 2012-Server gehostet wird.
Die Datenbank enthält zwei Tabellen mit folgenden Definitionen:

Weltweite Kunden bestellen aus mehreren Ländern.
Sie müssen das Land anzeigen, aus dem jeder Kunde die meisten Bestellungen aufgegeben hat.
Welche Transact-SQL-Abfrage verwenden Sie?
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
VON
(SELECT c.CustomerID, c.CustomerName, o.ShippingCountry,
RANK () ÜBER (PARTITION NACH CustomerID
ORDER BY COUNT (o.OrderAmount) ASC) AS Rnk
VOM KUNDEN c
INNER JOIN Bestellungen o
ON c.CustomerID = o.CustomerID
GROUP BY c.CustomerID, c.CustomerName, o.ShippingCountry) cs
WO Rnk = 1
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
VOM KUNDEN c
INNER JOIN
(SELECT Kundennummer, Versandland,
COUNT (OrderAmount) DESC) ALS OrderAmount
FROM Bestellungen
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
BESTELLEN NACH OrderAmount DESC
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
VOM KUNDEN c
INNER JOIN
(SELECT Kundennummer, Versandland,
RANK () ÜBER (PARTITION NACH CustomerID
ORDER BY COUNT (OrderAmount) DESC) AS Rnk
FROM Bestellungen
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
WO o.Rnk = 1
D. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
VOM KUNDEN c
INNER JOIN
(SELECT Kundennummer, Versandland,
RANK () ÜBER (PARTITION NACH CustomerID
BESTELLUNG NACH BESTELLBETRAG DESC) ALS Rnk
FROM Bestellungen
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
WO o.Rnk = 1
Answer: C