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SAP C-S4FTR-2023 exam
  • Exam Code: C-S4FTR-2023
  • Exam Name: SAP Certified Associate - SAP S/4HANA Cloud Private Edition - Treasury
  • Version: V12.35
  • Q & A: 70 Questions and Answers
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Price: $49.98 

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NEW QUESTION: 1
When creating a guest account on Cisco identity Services Engine.
Which option in the sponsor portal allows for the guest credentials to be used for RADIUS authentication without requiring the guest user to log into the guest portal?
A. Check the box to send email not send email notification id the guest user name is based on the email address.
B. Set the Time Profile to Radius 1Day
C. Set the Guest role to Guest
D. Set the Guest role to Activated guest
Answer: D

NEW QUESTION: 2
DRAG DROP
You are adding a function to a membership tracking application. The function uses an integer named memberCode as an input parameter and returns the membership type as a string.
The function must meet the following requirements:
* Return "Non-Member" if the memberCode is 0.
* Return "Member" if the memberCode is 1.
* Return "Invalid" if the memberCode is any value other than 0 or 1.
You need to implement the function to meet the requirements.
How should you complete the relevant code? (To answer, drag the appropriate statements to the correct locations in the answer area. Each statement may be used once, more than once, or not at all. You may need to drag the split bar between panes or scroll to view content.)

Answer:
Explanation:

Explanation:

Example:
int caseSwitch = 1;
switch (caseSwitch)
{
case 1:
Console.WriteLine("Case 1");
break;
case 2:
Console.WriteLine("Case 2");
break;
default:
Console.WriteLine("Default case");
break;
}

NEW QUESTION: 3
どの二つ機能が、ベース許可の上にシスコWCSプラス許可で利用できますか?
(2を選んでください)
A. 特別危険な発見
B. 2つのシスコWCS駅の間の高い有効性
C. 最も近いAPへのクライアント場所
D. 危険なAPsの自動発見と封じ込めまたは通知
E. 機動性業務用エンジン管理
Answer: B,E

NEW QUESTION: 4





A. CREATE TRIGGER TrgVwEmployeeON VwEmployeeFOR INSERTASBEGININSERT
INTO Person(Id, FirstName, LastName)SELECT Id, FirstName, LastName, FROM insertedINSERT INTO Employee(PersonId, EmployeeNumber)SELECT Id, EmployeeNumber FROM insertedEND
B. CREATE TRIGGER TrgVwEmployeeON VwEmployeeINSTEAD OF
INSERTASBEGININSERT INTO Person(Id, FirstName, LastName)SELECT Id, FirstName, LastName FROM VwEmployeeINSERT INTO Employee(PersonID, EmployeeNumber)SELECT Id, EmployeeNumber FROM VwEmployeeEND
C. CREATE TRIGGER TrgVwEmployeeON VwEmployeeINSTEAD OF
INSERTASBEGINDECLARE @ID INT, @FirstName NVARCHAR(25),@LastName
NVARCHAR(25), @PersonID INT,@EmployeeNumber NVARCHAR(15)SELECT @ID
ID, @FirstName = FirstName,@LastName = LastName, @EmployeeNumber
EmployeeNumberFROM insertedINSERT INTO Person(Id, FirstName,
LastName)VALUES(@ID, @FirstName, @LastName)INSERT INTO Employee(PersonID, EmployeeNumber)VALUES(@PersonID, @EmployeeNumberEND
D. CREATE TRIGGER TrgVwEmployeeON VwEmployeeINSTEAD OF
INSERTASBEGININSERT INTO Person(Id, FirstName, LastName)SELECT Id, FirstName, LastName, FROM insertedINSERT INTO Employee(PersonId, EmployeeNumber)SELECT Id, EmployeeNumber FROM insertedEND
Answer: D

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