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NEW QUESTION: 1
あなたは、Microsoft SQL Server 2012サーバーでホストされているアプリケーションのデータベース開発者です。
データベースには、次の定義を持つ2つのテーブルが含まれています。

グローバルな顧客は、いくつかの国から注文します。
各顧客が最も多く注文した国を表示する必要があります。
どのTransact-SQLクエリを使用しますか？
A. SELECT c.CustomerID、c.CustomerName、o.ShippingCountry
顧客cから
インナージョイン
（SELECT CustomerID、ShippingCountry、
RANK（）オーバー（CustomerIDによるパーティション）
ORDER BY COUNT（OrderAmount）DESC）AS Rnk
FROM注文
GROUP BY CustomerID、ShippingCountry）AS o
ON c.CustomerID = o.CustomerID
o.Rnk = 1の場合
B. SELECT c.CustomerID、c.CustomerName、o.ShippingCountry
顧客cから
インナージョイン
（SELECT CustomerID、ShippingCountry、
COUNT（OrderAmount）AS OrderAmount
FROM注文
GROUP BY CustomerID、ShippingCountry）AS o
ON c.CustomerID = o.CustomerID
ORDER BY OrderAmount DESC
C. CustomerID、CustomerName、ShippingCountryを選択します
から
（SELECT c.CustomerID、c.CustomerName、o.ShippingCountry、
RANK（）OVER（PARTITION BY c.CustomerID
ORDER BY COUNT（o.OrderAmount）ASC）AS Rnk
顧客cから
インナージョインオーダーo
ON c.CustomerID = o.CustomerID
GROUP BY c.CustomerID、c.CustomerName、
o.ShippingCountry）cs
WHERE Rnk = 1
D. SELECT CustomerID、CustomerName、ShippingCountry
から
（SELECT c.CustomerID、c.CustomerName、
o。 ShippingCountry、
RANK（）OVER（PARTITION BY c。CustomerID
ORDER BY o。 OrderAmount DESC）AS Rnk
顧客cから
インナージョインオーダーo
ON c.CustomerID = o.CustomerID
GROUP BY c.CustomerID、c.CustomerName、
o.ShippingCountry）cs
WHERE Rnk = 1
Answer: D

NEW QUESTION: 2
リスク管理の最も効果の低い形式はどれですか？
A. 人に基づく予防管理。
B. 人に基づく探偵のコントロール。
C. システムベースの予防管理。
D. システムベースの探偵制御。
Answer: B

NEW QUESTION: 3
Click the Exhibit button.
-- Exhibit -user@PE1# show protocols mpls userel-switched-path LSP-1 {
from 101.101.101.1;
to 103.103.103.1; } userel-switched-path LSP-2 {
from 101.101.101.1;
to 103.103.103.1; } interface ge-0/0/0.0;
user@PE1# show protocols ldp interface lo0.0;
user@PE1# show protocols l2circuit
neighbor 103.103.103.1 { interface ge-0/0/3.300 { virtual-circuit-id 300; }
}
user@PE1# show interfaces ge-0/0/3 flexible-vlan-tagging; encapsulation flexible-ethernet-services;
unit 300 { encapsulation vlan-ccc; vlan-id 300;
}
user@PE1# show protocols l2circuit
neighbor 103.103.103.1 { interface ge-0/0/3.300 { virtual-circuit-id 300; community test-community; }
}
user@PE1# show policy-options community test-community members 300:300; -- Exhibit -
Given the topology shown below: CE1-PE1-P-PE2-CE2
PE1 and PE2 have two equal-cost RSVP LSPs (LSP-1 and LSP-2). They form a Layer 2 circuit between CE1 and CE2. You are asked to map their traffic to take LSP-1. The exhibit shows the current configuration of PE1. The correct configuration has been completed on the other routers.
Which two configurations must be added to PE1 to ensure that this traffic is always carried on LSP-1? (Choose two.)
A. policy-statement mapping-l2ckt-to-lsp {
term 1 {
from community test-community;
then {
accept;
}
}
}
user@PE1# show routing-options
B. forwarding-table {
export mapping-l2ckt-to-lsp;
} user@PE1# show policy-options
C. policy-statement mapping-l2ckt-to-lsp {
term 1 {
from community test-community;
then {
install-nexthop lsp LSP-1;
}
}
}
user@PE1# show policy-options
D. forwarding-table {
import mapping-l2ckt-to-lsp;
}
user@PE1# show routing-options
Answer: B,C