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NEW QUESTION: 1
It involves identification and selection of a patient's medical record or group of records after the patient has been
discharged from the hospital or clinic. Many proponents of medical record review believe it to be the most accurate
method of data collection. What is it?
A. Retrospective data collection
B. Data collection forms
C. Prospective data collection
D. Scanners
Answer: A

NEW QUESTION: 2
Refer to the exhibit.

Which one statement is true?
A. Traffic from the 172.16.0.0/16 network will be blocked by the ACL.
B. The 10.0.0.0/8 network will not be advertised by Router B because the network statement for the
10.0.0.0/8 network is missing from Router B.
C. Router B will not advertise the 10.0.0.0/8 network because it is blocked by the ACL.
D. The 10.0.0.0/8 network will not be in the routing table on Router B.
E. Users on the 10.0.0.0/8 network can successfully ping users on the 192.168.5.0/24 network, but users on the 192.168.5.0/24 cannot successfully ping users on the 10.0.0.0/8 network.
Answer: C

NEW QUESTION: 3
Which four are primitive integer types in Java? (Choose four.)
A. long
B. short
C. byte
D. int
E. double
F. nibble
G. float
Answer: A,B,C,D

NEW QUESTION: 4
Your network contains two DHCP servers. The DHCP servers are named DHCP1 and DHCP2. The internal network contains 1,000 DHCP client computers that are located on a single subnet. A router separates the internal network from the Internet. The router has a single IP address on the internal interface.
DHCP1 has the following scope information:
Starting IP address: 172.16.0.1
Ending IP address: 172.16.7.254
Subnet mask: 255.255.240.0 You need to provide a fault tolerant DHCP infrastructure that supports the client computers on the internal network. In the event that a DHCP server fails, all client computers must be able to obtain a valid IP address.
How should you configure DHCP2?
A. Create a scope for the subnet 172.17.0.0/16. Configure the scope to use a starting IP address of
172.17.0.1 and an ending IP address of 172.17.255.254.
B. Create a scope for the subnet 172.16.0.0/21. Configure the scope to use a starting IP address of
172.16.0.1 and an ending IP address of 172.16.15.254.
C. Create a scope for the subnet 172.16.8.0/21. Configure the scope to use a starting IP address of
172.16.8.1 and an ending IP address of 172.16.10.254.
D. Create a scope for the subnet 172.16.0.0/20. Configure the scope to use a starting IP address of
172.16.8.1 and an ending IP address of 172.16.15.254.
Answer: D
Explanation:
Explanation
Explanation/Reference:
Network 255.255.240.0 = /20 -> 4096-2 addresses
255.255.255.0 = /24 -> 256-2 addresses
255.255.254.0 = /23 -> 512-2 addresses
255.255.252.0 = /22 -> 1024-2 addresses
255.255.248.0 = /21 -> 2048-2 addresses
IP address 172.16.0.1 to 172.16.7.254 -> 8*256 -2 = 2048-2 addresses
There are 2048-2 addresses left belind.
Option B (172.16.0.0/21) is ruled out because 172.16.0.1 to 172.16.15.254 are belonged to /20 (not /21) network
Option C (172.16.8.0/21) is ruled out because 172.16.8.1 to 172.16.10.254 contain 3*256-2 = 766
addresses only (insufficient for 1,000 clients)
Option D (172.17.0.0) is ruled out because of different network 172.17.0.0/16 (vs 172.16.0.0/20)