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Oracle 1z0-1051-23 exam
  • Exam Code: 1z0-1051-23
  • Exam Name: Oracle Learning Cloud 2023 Implementation Professional
  • Version: V12.35
  • Q & A: 70 Questions and Answers
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NEW QUESTION: 1
You are modifying an existing application that manages employee payroll. The application includes a class named PayrollProcessor. The PayrollProcessor class connects to a payroll database and processes batches of paychecks once a week.
You need to ensure that the PayrollProcessor class supports iteration and releases database connections after the batch processing completes.
Which two interfaces should you implement? (Each correct answer presents part of the complete solution.
Choose two.)
A. IEquatable
B. IDisposable
C. IComparable
D. IEnumerable
Answer: B,D
Explanation:
Explanation
B: IEnumerable to implement iteration.
Exposes an enumerator, which supports a simple iteration over a non-generic collection.
C: IDisposable Interface to implement disposing connections.
Defines a method to release allocated resources.
The primary use of this interface is to release unmanaged resources.

NEW QUESTION: 2
Which of the following asymmetric encryption algorithms is based on the difficulty of factoring LARGE numbers?
A. International Data Encryption Algorithm (IDEA)
B. Elliptic Curve Cryptosystems (ECCs)
C. RSA
D. El Gamal
Answer: C
Explanation:
Explanation/Reference:
Explanation:
RSA is derived from the last names of its inventors, Rivest, Shamir, and Addleman.
This algorithm is based on the difficulty of factoring a number, N, which is the product of two large prime numbers. These numbers may be 200 digits each. Thus, the difficulty in obtaining the private key from the public key is a hard, one-way function that is equivalent to the difficulty of finding the prime factors of N.
In RSA, public and private keys are generated as follows:
Choose two large prime numbers, p and q, of equal length, compute p3q 5 n, which is the public

modulus.
Choose a random public key, e, so that e and (p - 1)(q - 1) are relatively prime.

Compute e x d = 1 mod (p - 1)(q - 1), where d is the private key.

Thus, d = e-1 mod [(p - 1)(q - 1)]

From these calculations, (d, n) is the private key and (e, n) is the public key.
Incorrect Answers:
A: El Gamal is based not on the difficulty of factoring large numbers but on calculating discrete logarithms in a finite field.
B: Elliptic Curve Cryptosystems (ECCs) are not based on the difficulty of factoring large numbers.
D: International Data Encryption Algorithm (IDEA) is not based on the difficulty of factoring large numbers.
References:
Krutz, Ronald L. and Russel Dean Vines, The CISSP Prep Guide: Mastering the Ten Domains of Computer Security, John Wiley & Sons, New York, 2001, p. 148

NEW QUESTION: 3
회사 D는 http // www.companyd.com에서 액세스하는 Amazon S3에서 회사 웹 사이트를 운영하고 있습니다. 그들의 마케팅 팀이 새로운 웹 글꼴을 S3 종점에서 액세스 한 별도의 S3 버킷에 게시했습니다.
https://s3-us-west-1.amazonaws.com/cdfonts. 새로운 웹 글꼴을 테스트하는 동안 회사 D는 웹 글꼴이 브라우저에 의해 차단되고 있음을 인식했습니다.
회사 D가 웹 글꼴이 브라우저에 의해 차단되지 않도록 하려면 어떻게 해야 합니까?
A. 웹 사이트의 cdfonts 버킷에있는 웹 글꼴 요청에 Content-MD5 헤더 추가
B. 모든 사용자가 액세스 할 수 있도록 cdfonts 버킷에 정책을 만듭니다.
C. CORS 구성을 작성하여 원본 교차 요청을 허용하도록 cdfonts 버킷 구성
D. 각 웹 글꼴에 대해 cdfonts 버킷에서 버전 관리 사용
Answer: C

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