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NEW QUESTION: 1
You need to create an attendance log for the supervisor.
Which four actions should you perform in sequence? To answer, move the appropriate actions from the list of actions to the answer area and arrange them in the correct order.
NOTE: More than one order of answer choices is correct. You will receive credit for any of the correct orders you select.

Answer:
Explanation:

Explanation

NEW QUESTION: 2
You are the project manager of GHT project. You have analyzed the risk and applied appropriate controls. In turn, you got residual risk as a result of this. Residual risk can be used to determine which of the following?
A. Whether the benefits of such controls outweigh the costs
B. The area that requires more control
C. Status of enterprise's risk
D. is incorrect. Appropriate control can only be determined as the result of risk
assessment, not through residual risk.
E. Explanation:
Residual risk can be used by management to determine:
Which areas require more control Whether the benefits of such controls outweigh the costs
As residual risk is the output that comes after applying appropriate controls, so it can also estimate
the area which need more sophisticated control. If the cost of control is large that its benefits then
no control is applied, hence residual risk can determine benefits of these controls over cost.
F. Appropriate controls to be applied next
Answer: A,B,D,E
Explanation:
is incorrect. Status of enterprise's risk can be determined only after risk monitoring.

NEW QUESTION: 3
Jerry was 1/3 as young as his grandfather 15 years ago. If the sum of their ages is 110, how old is Jerry's grandfather?
A. 0
B. 1
C. 2
D. 3
E. 4
Answer: D
Explanation:
Explanation/Reference:
Explanation:
This uses two algebraic equations to solve for the age. Jerry (J) and his grandfather (G) have a sum of ages of 110 years. Therefore, J + G = 110. Jerry was one-third as young as his grandfather 15 years ago.
Therefore, J - 15 = 1/3 (G - 15). Solve the first equation for J: J = 110-G. Now substitute this value of J into the second equation: 110 - G - 15 = 1/3 (G - 15). Solve for G: 95 - G = 1/3 G -5; 100 = 4/3 G; G
75.