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Google ChromeOS-Administrator exam
  • Exam Code: ChromeOS-Administrator
  • Exam Name: Professional ChromeOS Administrator Exam
  • Version: V12.35
  • Q & A: 70 Questions and Answers
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NEW QUESTION: 1
どの3つの ESPのフィールドは、送信時に暗号化されることができますか? (3を選択してください。)
A. パディング
B. パディング長
C. シーケンス番号
D. セキュリティパラメータインデックス
E. Macアドレス
F. 次のヘッダー
Answer: A,B,F
Explanation:
Explanation
The packet begins with two 4-byte fields (Security Parameters Index (SPI) and Sequence Number). Following these fields is the Payload Data, which has substructure that depends on the choice of encryption algorithm and mode, and on the use of TFC padding, which is examined in more detail later. Following the Payload Data are Padding and Pad Length fields, and the Next Header field. The optional Integrity Check Value (ICV) field completes the packet.
Source: https://tools.ietf.org/html/rfc4303#page-14

NEW QUESTION: 2
You have three devices enrolled .n Microsoft Intune as shown .n the following table.

For each of the following statements, select Yes if the statement is true. Otherwise, select No.
NOTE: Each correct selection is worth one point.

Answer:
Explanation:

Explanation


NEW QUESTION: 3
What has the highest precedence for evaluation of the access control list?
A. Last in multi-group permission
B. User principals
C. First in multi-group permission
D. Group principals
Answer: B

NEW QUESTION: 4
Which one of the following queries selects the customer whose order has the highest total price?
A. CriteriaBuilder cb = ...
Criteria Query <Customer> cq = cb.create Query (Customer.class);
Root<Customer> c = cq.from(Customer.class);
Join<Customer, Order> o = c.join(Customer__.orders);
cq.select(c).distinct(true);
Subquery<Double> sq = cq.subquery(Double.class);
Root<Order> subo = cq.correlate(o);
sq.select(cb.max(subo.get(Order_.totalPrice)));
cq.where(cb.equal(o.get(Order_.totalPrice), cb.all(sq)));
B. CriteriaBuilder cb = ...
CriteriaQuery<Customer> cq = cb.createQuery(Customer.class);
Root<Customer> c = cq.from(Customer.class);
Join<Customer, Order> o = c.join(Customer_.orders);
cq.select(c).distinct(true);
Subquery<Double> sq = cq.subquery(Double.class);
Root<Order> subo = sq.from(Order.class);
sq. select (ci: . max ( subo . get (Order_ . Total Price) ) ) ;
cq.where(sq.all(o.gei(Order_.totalPrice)));
C. CriteriaBuilder cb = ...
CriteriaQuery<Customer> cq = cb.createquery(customer.class)
Root<Customer> c = cq.from(Customer.class);
Join<Customer, Order> o = c.join(Customer__.orders);
cq.select(c).distinct(true);
Subquery<Double> sq = cq.subquery(Double.class);
Root<Order> subo = cq.correlate(o);
sq.select(cb.max(subo.get(Order_.totalPrice)));
cq.where(cb.equal(o.get(Order_.totalPrice), cb.all(sq)));
D. CriteriaBuilder cb = ...
CriteriaQuery<Customer> cq = cb.cteateQuery(Customer.class);
Root<Customer> c = cq.from(Customer.class);
Join<Customer, Order> o = c.join(Customer__.orders);
cq.select(c).distinct(true);
Subquery<Double> sq = cq.subquery(Double.class);
Root<Order> subo = cq.correlate(o);
sq.select(cb.max(subo.get(Order_.totalPrice)));
cq.where(cb.equal(o.get(Order_.totalPrice), cb.all(sq)));
Answer: C

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