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NEW QUESTION: 1
Which configuration method can be used to add the trunk port ethernet0/1 of the switch to VLAN 4? (multiple choice)
A. [Switch]vlan 4 [Switch -Ethernet0/1]port trunk permit vlan 4
B. [Switch]vlan 4 [Switch-vlan4]port trunk ethernet 0/1
C. [Switch]vlan 4 [Switch-vlan4]port ethernet 0/1
D. [Switch]vlan 4 [Switch-Ethernet0/1]port trunk pvid vlan 4
Answer: A,C,D

NEW QUESTION: 2
組織が既知の悪意のあるドメインからスパムメールを受信して​​いる最初のTCP通信中にセッションを防ぐために何を構成する必要がありますか？
A. 通信を停止および拒否するようにポリシーを構成します
B. TCP接続をリセットするようにCiscoESAを設定します。
C. 悪意のある電子メールを隔離するようにポリシーを構成します。
D. 悪意のある電子メールをドロップするようにCiscoESAを設定します。
Answer: D
Explanation:
Explanation
https://www.cisco.com/c/en/us/support/docs/security/email-security-appliance/118219-configure-esa-00.html

NEW QUESTION: 3
You are developing an application that includes a class named Kiosk. The Kiosk class includes a static property named Catalog. The Kiosk class is defined by the following code segment. (Line numbers are included for reference only.)

You have the following requirements:
* Initialize the _catalog field to a Catalog instance.
* Initialize the _catalog field only once.
* Ensure that the application code acquires a lock only when the _catalog object must be instantiated.
You need to meet the requirements.
Which three code segments should you insert in sequence at line 09? (To answer, move the appropriate code segments from the list of code segments to the answer area and arrange them in the correct order.)

Answer:
Explanation:

Explanation

After taking a lock you must check once again the _catalog field to be sure that other threads didn't instantiated it in the meantime.

NEW QUESTION: 4
Refer to the exhibit.

An architect must design an IP addressing scheme for a multisite network connected via a WAN transit. The campus site must accommodate 12,000 devices and the branch sites must accommodate 1,000 devices. Which address scheme optimizes network device resources, contains convergence events to the different blocks of the network, and ensures future growth of the network?
A. * Campus: 10.0.0.0/20
* Branch1: 10.0.64.0/21
* Branch2: 10.0.128.0/21
B. * Campus: 10.0.0.0/10
* Branch1: 10.64.0.0/10
* Branch2: 10.128.0.0/10
C. * Campus: 10.0.0.0/18
* Branch1: 10.0.192.0/21
* Branch2: 10.0.200.0/21
D. * Campus: 10.0.0.0/16
* Branch1: 10.255.0.0/20
* Branch2: 10.255.16.0/20
Answer: C