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NEW QUESTION: 1
Select each Application Design Requirement on the left and drag it to the appropriate Design Approach on the right.

Answer:
Explanation:

NEW QUESTION: 2
46
Refer to the exhibit.

Which statement about this COS-DSCP mapping is true?
A. The default COS is mapped to DSCP 32.
B. COS 3 is mapped to the expedited forwarding DSCP.
C. COS 16 is mapped to DSCP 2.
D. This mapping is the default COS-DSCP mapping on Cisco switches.
Answer: B
Explanation:
Explanation/Reference:
Explanation:

NEW QUESTION: 3
Refer to the exhibit. Customer is planning to deploy a clustering over the WAN UCM topology with 2 subscribers at site 1 and 2 subscribers at site 2.
How much bandwidth would be required between site 1 and site 2 to for database replication?

A. 6.176 Mbps
B. 1.544 Mbps
C. 3.088 Mbps
D. 4.632 Mbps
E. 7.772 Mbps
Answer: D
Explanation:
Consider two sites, Site 1 and Site 2, with Unified CM clustered over the WAN across these two sites that are 80 msec round-trip time apart. Site 1 has one publisher, one combined TFTP and music on hold (MoH) server, and two Unified CM subscriber servers. Site 2 has one TFTP/MoH server and two Unified CM subscriber servers. Site 1 has 5000 phones, each having one DN; and Site 2 has 5000 phones, each having one DN. During the busy hour, 2500 phones in Site 1 call
2500 phones in Site 2, each at 3 BHCA. During that same busy hour, 2500 phones in Site 2 also call 2500 phones in Site 1, each at 3 BHCA. In this case:
Total BHCA during the busy hour = 2500*3 + 2500*3 = 15,000
Total bandwidth required between the sites = Total ICCS bandwidth + Total database bandwidth Because total BHCA is 15,000 (greater than 10,000), we can use the formula to calculate:
Total ICCS bandwidth = (15,000/10,000) * (1 + 0.006*80) = 2.22 Mbps
Total database bandwidth = (Number of servers remote to the publisher) * 1.544 = 3 * 1.544 =
4.632 Mbps
http://www.cisco.com/c/en/us/td/docs/voice_ip_comm/cucm/srnd/7x/uc7_0/models.html