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NEW QUESTION: 1
User access layer is composed of various types ( ).
A. MCU
B. GK
C. Terminal
D. GW
Answer: C

NEW QUESTION: 2
Why does compiled code pose more risk than interpreted code?
A. Because malicious code can be embedded in the compiled code and can be difficult to detect.
B. Because compilers are not reliable.
C. It does not. Interpreted code poses more risk than compiled code.
D. Because the browser can safely execute all interpreted applets.
Answer: A
Explanation:
Since the compiled code has already been translated to binary language (the language understanded natively by the computers), its very difficult for us (the humans) to detect malicious code inside an application, this is because its not apparently visible, you have to find that malicious code through the behavior of the program. Instead, when we talk about Interpreted code, we use a language interpreter, that is a piece of software that allows the end-user to write a program in some human-readable language, and have this program executed directly by the interpreter. This is in contrast to language compilers, that translate the human-readable code into machine-readable code, so that the end-user can execute the machine-readable code at a later time. This is far more easier to detect malicious code inside the programs, you just need to see what piece of code produced the undesired action.

NEW QUESTION: 3
Refer to the exhibit.

Which address and mask combination represents a summary of the routes learned by EIGRP?
A. 192.168.25.28 255.255.255.252
B. 192.168.25.28 255.255.255.240
C. 192.168.25.0 255.255.255.240
D. 192.168.25.16 255.255.255.252
E. 192.168.25.0 255.255.255.252
F. 192.168.25.16 255.255.255.240
Answer: F
Explanation:
The binary version of 20 is 10100.
The binary version of 16 is 10000.
The binary version of 24 is 11000.
The binary version of 28 is 11100.
The subnet mask is /28. The mask is 255.255.255.240.
Note:
From the output above, EIGRP learned 4 routes and we need to find out the summary of them:
+
192.168.25.16
+
192.168.25.20
+
192.168.25.24
+
192.168.25.28
-> The increment should bE. 28 - 16 = 12 but 12 is not an exponentiation of 2 so we must choose
16 (24). Therefore the subnet mask is /28 (=1111 1111.1111 1111.1111 1111.11110000) =
255.255.255.240.
So,the best answer should be 192.168.25.16 255.255.255.240.