EC-COUNCIL 212-89 Reliable Braindumps - Answers 212-89 Real Questions, 212-89 Mock Test - Hospital

EC-COUNCIL 212-89 exam
  • Exam Code: 212-89
  • Exam Name: EC Council Certified Incident Handler (ECIH v3)
  • Version: V12.35
  • Q & A: 70 Questions and Answers
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A technician has cleaned the inside with a paper vacuum, but printer continues to jam. Which of the following would BEST resolve the issue?<br/><strong>A.</strong> Installing a new transfer kit<br/><strong>B.</strong> Replacing the pickup rollers<br/><strong>C.</strong> Replacing the toner cartridge<br/><strong>D.</strong> Replacing the fuser<br/><strong>Answer: A</strong><br/><br/></p><p><strong>NEW QUESTION: 2</strong><br/>Examine the data of the EMPLOYEES table.<br/>EMPLOYEES (EMPLOYEE_ID is the primary key. MGR_ID is the ID of managers and refers to the EMPLOYEE_ID)<br/><img src="d37522a668f5497e767dd1920fe9f1cb.jpg"/><br/>Which statement lists the ID, name, and salary of the employee, and the ID and name of the employee's manager, for all the employees who have a manager and earn more than 4000?<br/><strong>A.</strong> salary, <br/><strong>B.</strong> mgr_id "Mgr_id", m.emp_name "manager"<br/>FROM employees e, employees m<br/>WHERE e.mgr_id = m.employee_id<br/>AND e.salary &gt; 4000;<br/><strong>C.</strong> salary,<br/><strong>D.</strong> SELECT e.employee_id "Emp_id", e.emp_name "Employee", <br/><strong>E.</strong> mgr_id "Mgr_id", m.emp_name "Manager"<br/>FROM employees e, employees m<br/>WHERE e.employee_id = m.employee_id<br/>AND e.salary &gt; 4000;<br/><strong>F.</strong> salary, <br/><strong>G.</strong> SELECT e.employee_id "Emp_id", e.emp_name "Employee", <br/><strong>H.</strong> employee_id "Mgr_id", m.emp_name "Manager"<br/>FROM employees e, employees m<br/>WHERE e.mgr_id = m.employee_id<br/>AND e.salary &gt; 4000;<br/><strong>I.</strong> SELECT e.employee_id "Emp_id", e.emp_name "Employee",<br/><strong>J.</strong> SELECT e.employee_id "Emp_id", e.emp_name "Employee", <br/><strong>K.</strong> salary, <br/><strong>L.</strong> employee_id "Mgr_id", m.emp_name "Manager"<br/>FROM employees e, employees m<br/>WHERE e.mgr_id = m.mgr_id<br/>AND e.salary &gt; 4000;<br/><strong>M.</strong> SELECT employee_id "Emp_id", emp_name "Employee",<br/>salary,<br/>employee_id "Mgr_id", emp_name "Manager"<br/>FROM employees<br/>WHERE salary &gt; 4000;<br/><strong>Answer: C</strong><br/>Explanation:<br/>This statement lists the ID, name, and salary of the employee, and the ID and name of the employee's manager, for all the employees who have a manager and earn more than 4000<br/>Incorrect Answers<br/>A: This statement does not check does employee have a manager or not, so it will not provide correct result.<br/>B: Usage of "e.mgr_id = m.mgr_id" condition is wrong to achieve required result.<br/>D: This statement uses "m.mgr_id" to show manager's manager, not employ's manager.<br/>E: Usage of "WHERE e.employee_id = m.employee_id" condition is wrong to achieve required result.<br/>OCP Introduction to Oracle 9i: SQL Exam Guide, Jason Couchman, p. 118-122 Chapter 3: Advanced Data Selection in Oracle<br/><br/></p><p><strong>NEW QUESTION: 3</strong><br/>A company makes the payment in a currency different from the invoice and ledger currency. 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